3D Distance Calculator

Now determine the distance between points in three dimensional space with the helps of 3d distance calculator with steps.

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Table of Contents:

Introduction to 3D Distance Calculator:

3D Distance Calculator is an online tool that helps you to find the distance between points in three-dimensional space. Our tool simplifies the process of evaluating the length of a straight line between two points in 3D space.

3d Distance Calculator with Steps

The 3d distance formula calculator is an educational tool that helps you to teach your children, and students about the concept of distance between two points by using its formula through on an online platform through an online platform quickly and easily.

What is 3D Distance?

3D distance is a measurement process in which you find the distance between two points 3d (three-dimensional space) on a straight line. It means it has three coordinates (x1, y1, z1) and (x2, y2, z2) from two different points value.

The 3D distance method is used in various fields like physics, graphic designing, and engineering to find the distance and the direction of the objects.

Formula of 3D Distance:

The 3d distance formula has three coordinates of (x,y,z) from point A to point B of a straight line on a graph. The distance between two 3d points formula behind the 3D Distance Calculator is,

$$ =\; \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2 + (z_2 - z_1)^2} $$

(x1, y1, z1) is the coordinate value point A.

(x2, y2, z2) is the coordinate value point B.

How to Calculate 3D Distance?

To calculate the 3D distance between two points, the distance formula calculator 3d follows the (x,y,z) coordinates point value which you can use to get a solution. If you do not know about it then follow these detailed steps.

Step 1:

Identify the given coordinates values in the form of (x,y,z) of two points in 3D space.

Step 2:

Compute the differences between coordinates value from each dimension coordinate such as:

For the x-coordinates.

$$ \Delta x \;=\; x_2 - x_1 $$

For the y-coordinates,

$$ \Delta y \;=\; y_2 - y_1 $$

For the z-coordinates,

$$ \Delta z \;=\; z_2 - z_1 $$

Step 3:

Square each coordinates value which you get after taking the difference between them such as:

$$ (\Delta x)^2 $$

$$ (\Delta y)^2 $$

$$ (\Delta z)^2 $$

Step 4:

Put these coordinates values in the 3d distance formula.

$$ =\; \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2 + (z_2 - z_1)^2} $$

Step 5:

Add up all the squaring coordinates value results.

Step 6:

Lastly, take the square of the sum value of the given coordinates value for two points.

$$ Distance\; d \;=\; \sqrt{Sum} $$

By following these steps, you can accurately calculate the distance between any two points in three-dimensional space.

Solved Example of a 3D Distance:

A solved example of 3D distance is given below to let you understand the working process of 3D Distance Calculator.

Example: Find the 3d distance with the help of the given coordinates.

$$ (X_1,\; Y_1,\; Z_1) \;=\; (7, 4, 3) $$

$$ (X_2,\; Y_2,\; Z_2) \;=\; (17, 6, 2) $$

Solution:

The given coordinates between the two points are,

$$ (X_1,\; Y_1,\; Z_1) \;=\; (7, 4, 3) $$

$$ (X_2,\; Y_2,\; Z_2) \;=\; (17, 6, 2) $$

 

The formula of 3d distance,

$$ d \;=\; \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2 + (z_2 - z_1)^2} $$

Add the coordinates value in it,

$$ d \;=\; \sqrt{(17 - 7)^2 + (6 - 4)^2 + (2 - 3)^2} $$

Take the difference between the coordinates' value,

$$ d \;=\; \sqrt{(10)^2 + (2)^2 + (-1)^2} $$

Square these coordinate value,

$$ d \;=\; \sqrt{100 + 4 + 1} $$

Add them for simplification,

$$ d \;=\; \sqrt{105} $$

Lastly square it to get the distance value,

$$ d \;=\; 10.246951 $$

How to Use 3D Distance Calculator?

The 3d distance formula calculator is an easy-to-use tool, so you can easily use it to evaluate the distance from the given coordinates value for 3D space problems.

Before adding the input value in the distance formula calculator 3d for the solutions, you must follow some simple steps. These steps are:

  1. Enter the coordinates value (x1,y1,z1) for the first point in the input field.
  2. Enter the coordinates value (x2,y2,z2) for the second point in the input field.
  3. Recheck your input value for the finding distance before hitting the calculate button to start the calculation process in the 3d coordinate distance calculator.
  4. Click on the “Calculate” button to get the desired result of your given distance problem for two points.
  5. If you are trying our 3d euclidean distance calculator to check its accuracy in solution, use the load example to get more understanding.
  6. Click on the “Recalculate” button to get a new page for solving more 3d distance questions.

Output of 3d Distance Formula Calculator:

3D Distance Calculator gives you the solution to a given 3d distance problem when you add the input value to it that has,

  • Result Option:

You can click on the result option as it provides you with a solution for 3d distance questions

  • Possible Step:

When you click on the possible steps option of the 3d coordinate distance calculator, it provides you with the solution of the distance problem where all calculation steps are included.

Benefits of Distance Formula Calculator 3d:

The three dimensional distance calculator gives you multiple benefits whenever you use it to calculate the length between two points problems and to get their solutions. These benefits are:

  • Our 3d point distance calculator saves the time and effort that you consume in solving distance between two-point questions and getting solutions in a few seconds.
  • It is a free-of-cost tool that provides you with a solution to a given distance question of a straight line in 3-dimensional space without paying a single penny.
  • You can use this 3d euclidean distance calculator for practice to get familiar with this concept of coordinates distance easily.
  • It is an adaptive tool that allows you to find the length of a line with the help of given coordinates (x,y,z) value in three-dimensional space.
  • The 3d distance calculator is a trustworthy tool that provides you with accurate solutions as per your input to calculate the 3d distance problem.
Related References
Frequently Ask Questions

What is the distance from the origin of the 3-D space to the (1,1,1) point?

To calculate the distance from the origin (0,0,0) to the point (1,1,1) in 3D space, follow these steps that are given as:

The given coordinates value is (x1, y1, z1) is (0, 0, 0) and (x2, y2, z2) is (1,1,1). Find the difference between each coordinates.

$$ Difference\; in\; x-coordinates: Δ x \;=\; 1 - 0 \;=\; 1 $$

$$ Difference\; in\; y-coordinates: Δ y \;=\; 1 - 0 \;=\; 1 $$

$$ Difference\; in\; z-coordinates: Δ z \;=\; 1 - 0 \;=\; 1 $$

Then takes the square of each coordinate value,

$$ (Δ x)^2 \;=\; 1^2 \;=\; 1 $$

$$ (Δ y)^2 \;=\; 1^2 \;=\; 1 $$

$$ (Δ z)^2 \;=\; 1^2 \;=\; 1 $$

Add all the above coordinates values such as:

$$ Sum \;=\; 1 + 1 + 1 \;=\; 3 $$

The distance formula for three d coordinates is,

$$ \sqrt{(x_2 - x_1)^2} + (y_2 - y_1)^2 + (z_2 - z_1)^2 $$

Put the sum of the coordinates value in this formula,

$$ Distance \;d \;=\; \sqrt{3} $$

$$ d \;=\; \sqrt{3} ≈ 1.732 $$

How to find the distance between a point and a line in 2d

To find the distance between a point and a line in 2D space, use the formula derived from the perpendicular distance from a point to a line.

$$ d \;=\; \frac{|Ax_0 + By_0 + C|}{\sqrt{A^2 + B^2}} $$

Suppose an example of point and line in 2d space where Point P(3,4) and the line 2x − 3y + 6 = 0.

$$ Ax_0 + By_0 + C \;=\; ? $$

Compare with the given equation

$$ Ax_0 + By_0 + C \;=\; 2x − 3y + 6 \;=\; 0 $$

$$ A \;=\; 2,\; B \;=\; -3,\; C \;=\; 6 \;and\; x_0 \;=\; 3\; and\; y_0 \;=\; 4 $$

Put the coefficient value in it,

$$ Ax_0 + By_0 + C \;=\; 2(3) + (-3)(4) + 6 $$

$$ 6 - 12 + 6 \;=\; 0 $$

For the absolute value

$$ |0| \;=\; 0 $$

Now for the point value

$$ \sqrt{A_2} + B_2 = \sqrt{(2)^2 + (-3)^2} $$

$$ \sqrt{4 + 9} \;=\; \sqrt{13} $$

Put all these value in the above formula,

$$ d \;=\; \frac{|Ax_0 + By_0 + C|}{\sqrt{A^2 + B^2}} $$

$$ d \;=\; \frac{0}{\sqrt{13}} \;=\; 0 $$

How to calculate the perpendicular distance in 3d

To calculate the perpendicular distance from a point to a plane in 3D space, you can use the same formula for the plane equation. This distance is the shortest distance from the point to the plane, measured along a line perpendicular to the plane.

Identify the plane equation Ax + By + Cz + D = 0 and point coordinates P(x0, y0, z0). Apply the perpendicular distance formula which is given as:

$$ d \;=\; \frac{|Ax_0 + By_0 + Cz_0 + D|}{\sqrt{A^2 + B^2 + C^2}} $$

Add the given equation value in the above formula and solve it to get the perpendicular distance as a solution.

Find the distance between the two points given by P(6,4,-3) and Q(2,-8,3)

To find the distance between two points P(6,4,−3) and Q(2,−8,3) in 3D space, follow these steps:

Given that

$$ Point\; P \;=\; (6, 4, −3) $$

$$ Point\; Q \;=\; (2, −8, 3) $$

Compute the differences between each dimension

Difference in x-coordinates

$$ \Delta x \;=\; x_2 − x_1 \;=\; 2 − 6 \;=\; −4 $$

Difference in y-coordinates

$$ \Delta y \;=\; y_2 − y_1 \;=\; −8 −4 \;=\; −12 $$

Difference in z-coordinates

$$ \Delta z \;=\; z_2 − z_1 \;=\; 3−(−3) \;=\; 6 $$

Square the differences result,

$$ (Δx)^2 \;=\; (−4)^2 \;=\; 16 $$

$$ (Δy)^2 \;=\; (−12)^2 \;=\; 144 $$

$$ (Δz)^2 \;=\; (6)^2 \;=\; 36 $$

Sum the result of squared differences
$$ 16 + 144 + 36 \;=\; 196 $$

Take the Square Root,

$$ d \;=\; \sqrt{196} \;=\; 14 $$

How do you find the distance in 2d

To find the distance in 2d let us suppose an example with a solution to better understand about the calculation process of 2d distance.

Find the distance between two points P(1,2) and point Q(4,6). First compute the difference between coordinates value,

$$ Δ x \;=\; 4 - 1 \;=\; 3 $$

$$ Δ y \;=\; 6 - 2 \;=\; 4 $$

Square the above value,

$$ (Δ x)^2 \;=\; 3^2 \;=\; 9 $$

$$ (Δ y)^2 \;=\; 4^2 \;=\; 16 $$

Add up them,

$$ Sum \;=\; 9 + 16 \;=\; 25 $$

The distance formula for 2d is:

$$ d \;=\; \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} $$

Put the above values,

$$ Distance \;d \;=\; \sqrt{25} $$

Squaring the sum value for the distance between two points in 2d,

$$ d\; \sqrt{25} \;=\; 5 $$

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