Linear Independence Calculator

Welcome to our Linear Independence Calculator & Checker. It quickly tells you if a group of vectors are independent or not.

Table of Contents:

Introduction to Linear Independence Calculator With Steps:

Linear independence calculator is an online tool that is designed to determine whether the set of vectors is linearly independent or not. It checks the linear independence condition if a linear combination of vectors is equal to zero only when all coefficients of the combination are zero.

Linear Independence Calculator with Steps

Linear independence checker is a valuable tool for students, professionals, and anyone who is working on vector spaces in mathematics and related fields.

What is Linear Independence?

Linear algebra is a process in linear algebra, where a set of vectors {v1, v2,…, vn} in a vector space is said to be linearly independent if a number of vectors in the set can be defined as a linear combination of other sets.

Linear independence of a vector can be written as:

$$ c_1 v_1 + c_2 v_2 + … + c_n v_n \;=\; 0 $$

Where c1, c2,…, cn are scalar of the given vector, and it has only the trivial solution c1 = c2 = … = cn = 0.

How to Calculate Linear Independence?

To determine linear independence, utilize our linear independence calculator to automate the process. Alternatively, you can manually assess by starting with a set of vectors and applying various methods to ascertain if they are linearly independent. Follow these steps to understand how to verify the independence of a given set of vectors.

Step 1: Consider a set of vectors {v1, v2,…, vn}. These vectors are linearly independent of the equation: c1v1 + c2v2 + … + cnvn = 0. This scalar has the trivial solution c1 = c2 = … = cn = 0

Step 2: Make a matrix A in the form of a column matrix. For example, if v1,v2,…, and vnv are vectors in Rm, then A will be an m × n matrix.

$$ A \;=\; \left( \begin{matrix} | & | & … & | \\ v_1 & v_2 & … & v_n \\ | & | & … & | \\ \end{matrix} \right) $$

Step 3: To check for linear independence, solve the equation Ac=0, where c=(c1c2….,cn) is the vector of coefficients and 0 is the zero vector.

$$ c \;=\; \left( \begin{matrix} c_1 \\ c_2 \\ \vdots \\ c_n \\ \end{matrix} \right) $$

You can use the Gaussian elimination row reduction or determinant method to solve the given system.

Step 4: If the solution of the matrix is equal to zero as Ac = 0, then the vectors {v1, v2,…, vn} are linearly independent. If the solution is non-trivial (i.e., c ≠ 0), then the vectors are linearly dependent.

Practical Example of a Linear Independent:

Let's see an example of the linear independence of a vector with a solution to know about this concept effortlessly.

Example: Find the linear independence of a given set of vector:

$$ \left[ \left( \begin{matrix} 1 \\ 1 \\ -2 \\ \end{matrix} \right),\; \left( \begin{matrix} 1 \\ -1 \\ 2 \\ \end{matrix} \right),\; \left( \begin{matrix} 3 \\ 1 \\ 4 \\ \end{matrix} \right) \right] $$

Solution:

Suppose x , y and z are the given vector to form equation as x+y+z=0.

$$ x \left( \begin{matrix} 1 \\ 1 \\ -2 \\ \end{matrix} \right) + y \left( \begin{matrix} 1 \\ -1 \\ 2 \\ \end{matrix} \right) + z \left( \begin{matrix} 3 \\ 1 \\ 4 \\ \end{matrix} \right) \;=\; \left( \begin{matrix} 0 \\ 0 \\ 0 \\ \end{matrix} \right) $$

Make a matrix A using the element of vector x, y and z.

$$ \left( \begin{matrix} 1 & 1 & 3 \\ 1 & -1 & 1 \\ -2 & 2 & 4 \\ \end{matrix} \right) $$

Use the gauss elimination method to convert the above matrix into reduced echelon form,

$$ \left[ \begin{matrix} 1 & 1 & 3 \\ 1 & -1 & 1 \\ -2 & 2 & 4 \\ \end{matrix} \right] $$

$$ R_2 \leftarrow R_2 - R_1 $$

$$ =\; \left[ \begin{matrix} 1 & 1 & 3 \\ 0 & -2 & -2 \\ -2 & 2 & 4 \\ \end{matrix} \right] $$

$$ R_3 \leftarrow R_3 + 2 \times R_1 $$

$$ =\; \left[ \begin{matrix} 1 & 1 & 3 \\ 0 & -2 & -2 \\ 0 & 4 & 10 \\ \end{matrix} \right] $$

$$ R_2 \leftarrow R_2 \div -2 $$

$$ =\; \left[ \begin{matrix} 1 & 1 & 3 \\ 0 & 1 & 1 \\ 0 & 4 & 10 \\ \end{matrix} \right] $$

$$ R_3 \leftarrow R_2 - 4 \times R_2 $$

$$ =\; \left[ \begin{matrix} 1 & 1 & 3 \\ 0 & 1 & 1 \\ 0 & 0 & 6 \\ \end{matrix} \right] $$

$$ R_3 \leftarrow R_3 - 4 \times R_2 $$

$$ R_3 \leftarrow R_3 \div 6 $$

$$ =\; \left[ \begin{matrix} 1 & 1 & 3 \\ 0 & 1 & 1 \\ 0 & 0 & 1 \\ \end{matrix} \right] $$

$$ R_2 - R_3\; and\; R_1 - R_2 $$

And lastly after R1-2R3

$$ \left( \begin{matrix} 1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1 \\ \end{matrix} \right) $$

So x = y = z = 0 the only solution is the trivial solution then the given set of vectors is linearly independent.

How to Use the Linearly Independent Calculator?

Linear independent calculator have an easy-to-use interface, so you can easily use it to evaluate the linear independence of a given set solution. Before adding the input for the solutions of given vector space problems, you must follow some simple steps. These steps are:

  1. Add the number of vectors for the linearity of vectors.
  2. Add the size of the vector for the linearity of vectors.
  3. Enter the elements of the given vector in a set in the input box
  4. Review your input value for the vector before hitting the calculate button to start the calculation process in the linearly independent matrix calculator
  5. Click on the “Calculate” button to get the desired result of your given linear independent vector problem.
  6. If you want to try out our linear independence matrix calculator to check its accuracy in solution then use the load example.
  7. Click on the “Recalculate” button to get a new page for solving more linear combination questions.

Final Result of the Linear Independence Checker:

Linear independence of functions calculator gives you the solution to a given vector set problem when you add the input to it. It provides you with solutions . It may contain as:

  • Result Option:

You can click on the result option and it provides you with a solution of vector set linearly independent questions.

  • Possible Step:

When you click on the possible steps option it provides you with the solution of a linear independent problem where all calculation steps are included in detail.

Benefits of Using Linearly Independent Vectors Calculator:

Linear independence calculator with steps gives you multiple benefits whenever you use it to calculate linear independence problems and to get its solution immediately. These benefits are:

  • Our linearly independent calculator saves the time and effort that you consume in solving complex vector space questions in a few seconds.
  • It is a free-of-cost tool that provides you with a solution of a given vector to find its linear independence without paying a single penny.
  • It is an adaptive tool that allows you to find the linear independence from the given vectors in two or maybe three dimensions in a linear independent calculator.
  • You can use this linearly independent matrix calculator for practice so that you get a strong hold about this concept.
  • Linear independence matrix calculator is a trustworthy tool that provides you with the accurate solutions as per your input to calculate the Linear Independent problem.
Related References
Frequently Ask Questions

How to find linear dependence using determinants?

To find if a set of vectors is linearly dependent or not use the determinants, and follow these steps:

For example,

$$ v_1 \;=\; \left(\begin{matrix} 1 \\ 2 \\ 3 \\ \end{matrix} \right),\; v_2 \;=\; \left(\begin{matrix} 2 \\ 4 \\ 6 \\ \end{matrix} \right),\; and\; v_3 \;=\; \left( \begin{matrix} 1 \\ 0 \\ 1 \\ \end{matrix} \right) $$

Solution:

Make a matrix A with the help of the given vector,

$$ A \;=\; \left( \begin{matrix} 1 & 2 & 1 \\ 2 & 4 & 0 \\ 3 & 6 & 1 \\ \end{matrix} \right) $$

Find the determinant of matrix A,

$$ |D| \;=\; \left| \begin{matrix} 1 & 2 & 1 \\ 2 & 4 & 0 \\ 3 & 6 & 1 \\ \end{matrix} \right| $$

$$ =\; 1 \times \left|\begin{matrix} 4 & 0 \\ 6 & 1 \\ \end{matrix} \right| -2 \times \left|\begin{matrix} 2 & 0 \\ 3 & 1 \\ \end{matrix} \right| + 1 \times \left| \begin{matrix} 2 & 4 \\ 3 & 6 \\ \end{matrix} \right| $$

$$ =\; 1 \times (4 \times 1 - 0 \times 6) - 2 \times (2 \times 1 - 0 \times 3) + 1 \times (2 \times 6 - 4 \times 3) $$

$$ =\; 1 \times (4 + 0) - 2 \times (2 + 0) + 1 \times (12 - 12) $$

$$ =\; 1 \times (4) - 2 \times (2) + 1 \times (0) $$

$$ =\; 4 - 4 + 0 $$

$$ =\; 0 $$

Since |D| is equal to zero the given vector is linearly independent.

What is the difference between linear independence and dependence of vectors?

The concepts of linear independence and linear dependence are related to each other in vector vector space in linear algebra.

Linearly independent vectors span a space such that no vector in the set can be written as a combination of the others but the linear dependent vector cannot span the space. Linearly dependent vectors have redundancy in the set but some vectors can be represented as combinations of others. There exist non-trivial solutions to the equation c1v1 + c2v2 +…+ cnvn = 0 but not all coefficients are zero

On the other hand, linearly independent vectors point in different directions and cannot lie on the same line (in 2D) or plane (in 3D) or its span is the entire space. linearly dependent vectors lie on the same line (in 2D), plane (in 3D), or hyperplane not space the entire space.

Is the identity matrix linearly independent?

Yes, the identity matrix is linearly independent because its diagonal has an entity other than zero. To understand why, you can see the definition of linear independence which tells a set of vectors {v1, v2,…, vn} is linearly independent if the equation c1v1 + c2v2 +…+ cnvn = 0 has only the trivial solution c1 = c2 = …= cn = 0.

How do I check if vectors are linearly independent?

It is important to know if your solution of vector linearly independent is correct or not. You can use the determinant method for a matrix A whose columns are the vectors you want to check in a vector space. They are linearly independent if, and only if, the determinant of matrix A is equal to zero.

What is independence for multiple linear regression?

The independence of multiple linear regression refers to an assumption about the errors of the regression model. This assumption is crucial for the validity of the regression analysis. This assumption ensures that the statistical inferences drawn from the regression model are valid and unbiased.

The violations of the independence assumption can lead to inaccurate results and conclusions, emphasizing the importance of checking this assumption when analyzing data with regression models.

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